Titik tengah A dan A'
B\left(\dfrac{1+3}2,\dfrac{-2+4}2\right)=B(2,1)
B dilalui oleh garis {ax + by + 2 = 0}
\begin{aligned}
2a+b+2&=0\\
2a+b&=-2
\end{aligned}
Gradien garis AA'
\begin{aligned}
m_{AA'}&=\dfrac{y_{A'}-y_A}{x_{A'}-x_A}\\
&=\dfrac{4-(-2)}{3-1}\\
&=\dfrac62\\
&=3
\end{aligned}
gradien garis {ax + by + 2 = 0}
\begin{aligned}
m&=-\dfrac1{m_{AA'}}\\
-\dfrac{a}b&=-\dfrac13\\
\dfrac{a}b&=\dfrac13\\
b&=3a
\end{aligned}
\begin{aligned}
2a+b&=-2\\
2a+3a&=-2\\
5a&=-2\\
a&=-\dfrac25
\end{aligned}
\begin{aligned}
a+b&=a+3a\\
&=4a\\
&=4\left(-\dfrac25\right)\\
&=\boxed{\boxed{-\dfrac85}}
\end{aligned}
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